If the angle of incident ray is equal to the critical angle and ny is larger then nx the ray A follows the path shown in 3. On the contrary, if the ny is larger than nx and angle of incident ray is smaller than the critical angle then it follows the path shown in 2. If the nx is larger than the ny then light ray follows the path shown in 1 it approaches to the normal. We do not know the refractive indexes of the mediums. Find the critical angle of the rays coming from the medium A to B.Įxample: Which paths, given in the picture below, can be followed by the light ray A? Where Θc is critical angle and rays coming with an angle larger than Θc make total reflection.Įxample: Refractive indexes of medium A is 2, and medium B is 1,6. Now we use Snell’s law of refraction and find the equation of critical angle. However, third light coming with an angle larger than the critical angle does total reflection and can not pass to the second medium. Second light coming with an angle smaller than the critical angle, refracts and passes to the second medium. In the picture given above, first light is coming from the normal thus it does not reflect or refract it passes directly to the second medium. If the angle of incident ray is larger than the critical angle then it does not refract but it does total reflection. According to the angle of incident ray, at one point it does not refract but goes parallel to the boundary of the mediums. ![]() ![]() Thus, light refract away from the normal. Here, you see that light coming from the medium having larger refractive index to the smaller refractive index. According to this law reflecting, refracting or directly passing of light to the other medium is depends on angle of incident ray and refractive indexes of the mediums. In the previous section we learned Snell’s law of refraction. Rays with different angles coming from the source at the bottom of the water filled glass, refracted from the surface, reflected and directly pass to the second medium without any reflection and refraction.
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